移植到C#下效果：

源码:
static void Main(string[] args)
        {
            long tick0, tick1;
            tick0 = DateTime.Now.Ticks;
            double a = 1, b = 0, c = 0;  //关于兔子
            double g = 1;
            int n = 99;//需要计算的数据数
            Console.WriteLine("第1月1");
            for (int i = 1; i <= n; i++)
            {
                c=c+b;
                b=a;
                a=c;
                g=a+c+b;
                Console .WriteLine ("第{0}月{1}",i+1,g);
            }
            tick1 = DateTime.Now.Ticks;
            Console.WriteLine("运算{0}次，耗时{1}微秒", n, (tick1 - tick0) / 10);
            Console .ReadKey ();
        }