我的是这样的

#include<iostream>using namespace std;unsigned long long n,m,p;//n^m%punsigned long long f(unsigned long long x){ if(x==1) return n%p; if(x%2==0) //完全二分 { unsigned long long j=f(x/2); //储存f的值，不用调用2次 return j*j%p; } else { unsigned long long j=f((x-1)/2); return j*j*n%p; }}int main(){ cin>>n>>m>>p; cout<<f(m); return 0;}